EXERCISE 4.1
1. The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement. (Take the cost of a notebook to be Rs. \[\text{x}\] and that of a pen to be Rs. \[\text{y}\] )
Ans. Let the cost of a notebook be Rs. \[x\]and the cost of a pen be Rs. \[y\].
We know that the cost of a notebook is twice the cost of a pen.
Therefore, we can write the required linear equation in theform:
\[Cost\text{ }of\text{ }notebook\text{ }=\text{ }2\text{ }\times \text{ }Cost\text{ }of\text{ }pen~~\]
\[x=2y~\]
\[x-2y~=0\]
2. Express the following linear equations in the form \[\text{ax+by+c= 0}\] and indicate the values of \[\text{a}\] , \[\text{b}\] , \[\text{c}\] in each case:
(i) \[\text{2x+3y=9}\text{.3}\overline{\text{5}}\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[2x+3y=9.3\overline{5}\]
\[2x+3y-9.3\overline{5}=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=2\]
\[b=3\]
\[c=-9.3\overline{5}\]
(ii) \[\text{x-}\frac{\text{y}}{\text{5}}\text{-10=0}\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[x-\frac{y}{5}-10=0\]
\[5x-y-50=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=5\]
\[b=-1\]
\[c=-50\]
(iii) \[\text{-2x+3y=6}\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[-2x+3y=6\]
\[-2x+3y-6=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=-2\]
\[b=3\]
\[c=-6\]
(iv) \[\text{x=3y}\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[x=3y\]
\[x-3y=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=1\]
\[b=-3\]
\[c=0\]
(v) \[2x=-5y\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[2x=-5y\]
\[2x+5y=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=2\]
\[b=5\]
\[c=0\]
(vi) \[\text{3x+2=0}\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[3x+2=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=3\]
\[b=0\]
\[c=2\]
(vii) \[\text{y-2=0}\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[y-2=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=0\]
\[b=1\]
\[c=-2\]
(viii) \[\text{5=2x}\]
Ans. Writing the given equation in standard form \[\text{ax+by+c= 0}\] :
\[5=2x\]
\[-2x+5=0\]
Comparing this equation with standard form of the linear equation, \[\text{ax+by+c= 0}\] we have:
\[a=-2\]
\[b=0\]
\[c=5\]
NCERT Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables (Ex 4.1) Exercise 4.1
Opting for the NCERT solutions for Ex 4.1 Class 9 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 4.1 Class 9 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.
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NCERT Solutions for Class 9 Maths
Chapter 1 - Number System
Chapter 2 - Polynomials
Chapter 3 - Coordinate Geometry
Chapter 4 - Linear Equations in Two Variables
Chapter 5 - Introductions to Euclids Geometry
Chapter 6 - Lines and Angles
Chapter 7 - Triangles
Chapter 8 - Quadrilaterals
Chapter 9 - Areas of Parallelogram and Triangles
Chapter 10 - Circles
Chapter 11 - Constructions
Chapter 12 - Herons formula
Chapter 13 - Surface area and Volumes
Chapter 14 - Statistics
Chapter 15 - Probability
List of Exercises and Topics Covered in Linear Equation In Two Variable Class 9:
Exercise 4.1 - Linear Equations
Exercise 4.2 - Solution of a Linear Equation
Exercise 4.3 - Graph of a Linear Equation in Two Variables
Exercise 4.4 - Equations of Lines Parallel to the x-axis and y-axis